(R)=3.14r^2

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Solution for (R)=3.14r^2 equation: 



()=3.14R^2

We move all terms to the left:

()-(3.14R^2)=0

We add all the numbers together, and all the variables

-(3.14R^2)=0

We get rid of parentheses

-3.14R^2=0

a = -3.14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3.14)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$R=\frac{-b}{2a}=\frac{0}{-6.28}=0$

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